What is area y=(x^2)/2-4x+6,y= x/2-1,x=0,x=5 ?

The answer to area y=(x^2)/2-4x+6,y= x/2-1,x=0,x=5 is 157/12

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area y=(x^2)/2-4x+6,y= x/2-1,x=0,x=5

area

y = \frac{x ^{2}}{2} - 4 x + 6, y = \frac{x}{2} - 1, x = 0, x = 5

\frac{157}{12}

Decimal Notation

13.08333 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x

Solve

\int_{0}^{5} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x : \frac{157}{12}

The area is:

= \frac{157}{12}

\int \frac{441}{x ^{3} - 21 x ^{2}} d x

\int \frac{x ^{2}}{( 25 + x ^{2} ) ^{2}} d x

5 x y \frac{d y}{d x} = 1

y^{^{''}} - 3 y^{^{'}} - 12 y = 0

\frac{4 e ^{(- 2 s)}}{( s ^{2} - 4 s + 3 )}

What is area y=(x^2)/2-4x+6,y= x/2-1,x=0,x=5 ?
The answer to area y=(x^2)/2-4x+6,y= x/2-1,x=0,x=5 is 157/12