What is the solution for y^'=(xe^x)/(2y) ?

The solution for y^'=(xe^x)/(2y) is y=sqrt(e^xx-e^x+c_{1)},y=-sqrt(e^xx-e^x+c_{1)}

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y^'=(xe^x)/(2y)

y^{^{'}} = \frac{x e ^{x}}{2 y}

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

Solution steps

y^{'} (x) = \frac{x e ^{x}}{2 y}

Solve separable ODE:

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

x \to 0 lim (sin (\frac{1}{2}))

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What is the solution for y^'=(xe^x)/(2y) ?
The solution for y^'=(xe^x)/(2y) is y=sqrt(e^xx-e^x+c_{1)},y=-sqrt(e^xx-e^x+c_{1)}