What is the solution for x^{''}+x=e^{2t} ?

The solution for x^{''}+x=e^{2t} is x=c_{1}cos(t)+c_{2}sin(t)+1/5 e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+x=e^{2t}

x^{^{''}} + x = e^{2 t}

x = c_{1} cos (t) + c_{2} sin (t) + \frac{1}{5} e^{2 t}

Solution steps

x^{''} (t) + x = e^{2 t}

Solve linear ODE:

x = c_{1} cos (t) + c_{2} sin (t) + \frac{1}{5} e^{2 t}

x = c_{1} cos (t) + c_{2} sin (t) + \frac{1}{5} e^{2 t}

\frac{\partial}{\partial x} (ln (x + 8 y + 4 z))

x \to 0 lim (ln (x + 1))

\frac{6 x h + 3 h ^{2}}{h}

f (x) = - e^{x}

\int sin (2 θ) e^{s i n^{2} (θ)} d θ

What is the solution for x^{''}+x=e^{2t} ?
The solution for x^{''}+x=e^{2t} is x=c_{1}cos(t)+c_{2}sin(t)+1/5 e^{2t}