What is the integral from 1 to e of ln(10x) ?

The integral from 1 to e of ln(10x) is eln(10e)-e-ln(10)+1

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integral from 1 to e of ln(10x)

\int_{1}^{e} ln (10 x) d x

e ln (10 e) - e - ln (10) + 1

Decimal Notation

4.95649 \dots

Solution steps

\int_{1}^{e} ln (10 x) d x

Apply Integration By Parts

: [x ln (10 x) - \int 1 d x]_{1}^{e}

= [x ln (10 x) - \int 1 d x]_{1}^{e}

\int 1 d x = x

= [x ln (10 x) - x]_{1}^{e}

Compute the boundaries:

e ln (10 e) - e - ln (10) + 1

= e ln (10 e) - e - ln (10) + 1

y = sin^{2} (4 π t - 5)

\frac{d}{d x} (x^{π})

\frac{d}{d x} (x^{2} - 4 + 4 - y^{2})

\int x^{2} (x^{3} + 1)^{4} d x

\frac{\partial}{\partial x} (x^{2} + y^{2} + 48 - x y - 6 x)

What is the integral from 1 to e of ln(10x) ?
The integral from 1 to e of ln(10x) is eln(10e)-e-ln(10)+1