What is the derivative of sec(x-x) ?

The derivative of sec(x-x) is sec(x)tan(x)-1

What is the first derivative of sec(x-x) ?

The first derivative of sec(x-x) is sec(x)tan(x)-1

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\frac{d}{d x} (sec (x) - x)

sec (x) tan (x) - 1

Solution steps

\frac{d}{d x} (sec (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sec (x)) - \frac{d x}{d x}

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d x}{d x} = 1

= sec (x) tan (x) - 1

y = x^{2} + 4 x - 11, (2, - 1)

f (x) = 1 + x, x = 0

\frac{d}{d x} (2 1 - x^{2})

x \to \infty lim (x^{2} + x)

x^{2} \frac{d y}{d x} + x y = x^{2} e^{x}

What is the derivative of sec(x-x) ?
The derivative of sec(x-x) is sec(x)tan(x)-1
What is the first derivative of sec(x-x) ?
The first derivative of sec(x-x) is sec(x)tan(x)-1