What is (\partial)/(\partial x)(2xy-3xz^2) ?

The answer to (\partial)/(\partial x)(2xy-3xz^2) is 2y-3z^2

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(\partial)/(\partial x)(2xy-3xz^2)

\frac{\partial}{\partial x} (2 x y - 3 x z^{2})

2 y - 3 z^{2}

Solution steps

\frac{\partial}{\partial x} (2 x y - 3 x z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (3 x z^{2})

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (3 x z^{2}) = 3 z^{2}

= 2 y - 3 z^{2}

\int 5 sin^{4} (x co) s^{2} x d x

\frac{d}{d x} (\frac{x ^{2} + 2 x}{3 x + 6})

x \to - 1 lim (x^{3} - 2)

cot^{2} (sin (θ))

\frac{x}{u}

What is (\partial)/(\partial x)(2xy-3xz^2) ?
The answer to (\partial)/(\partial x)(2xy-3xz^2) is 2y-3z^2