What is the derivative of f(2x)^2-1 ?

The derivative of f(2x)^2-1 is 4x^2

What is the first derivative of f(2x)^2-1 ?

The first derivative of f(2x)^2-1 is 4x^2

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derivative of

f (2 x)^{2} - 1

4 x^{2}

Solution steps

\frac{d}{df} (f (2 x)^{2} - 1)

Simplify

f (2 x)^{2} - 1 : 4 f x^{2} - 1

= \frac{d}{df} (4 f x^{2} - 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{df} (4 f x^{2}) - \frac{d}{df} (1)

\frac{d}{df} (4 f x^{2}) = 4 x^{2}

\frac{d}{df} (1) = 0

= 4 x^{2} - 0

Simplify

= 4 x^{2}

x^{5} + 2 x^{4} - 11 x^{3} - 12 x^{2} + 36 x

\frac{d}{d x} (- \frac{1}{x ^{2}} - \frac{7}{x})

n = 9 \sum \infty e^{5 - 4 n}

4 - x^{2}, - x + 2

e^{2} X

What is the derivative of f(2x)^2-1 ?
The derivative of f(2x)^2-1 is 4x^2
What is the first derivative of f(2x)^2-1 ?
The first derivative of f(2x)^2-1 is 4x^2