What is (\partial)/(\partial x)(sin(x)cos(y)) ?

The answer to (\partial)/(\partial x)(sin(x)cos(y)) is cos(y)cos(x)

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(\partial)/(\partial x)(sin(x)cos(y))

\frac{\partial}{\partial x} (sin (x) cos (y))

cos (y) cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= cos (y) cos (x)

\frac{\partial}{\partial y} (cos (x^{2} + x y))

\int a^{u} d u

\frac{3}{t ^{2}}

\int cos^{3} (θ) d θ

\frac{\partial}{\partial x} (\frac{( x + y )}{x - y})

What is (\partial)/(\partial x)(sin(x)cos(y)) ?
The answer to (\partial)/(\partial x)(sin(x)cos(y)) is cos(y)cos(x)