What is the limit as x approaches pi/2 of ln(sin(x)) ?

The limit as x approaches pi/2 of ln(sin(x)) is 0

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limit as x approaches pi/2 of ln(sin(x))

x \to \frac{π}{2} lim (ln (sin (x)))

0

Solution steps

x \to \frac{π}{2} lim (ln (sin (x)))

Plug in the value

x = \frac{π}{2}

= ln (sin (\frac{π}{2}))

Simplify

ln (sin (\frac{π}{2})) : 0

= 0

\frac{2}{x}, 8 x, \frac{1}{2} x

x \to 3 lim (2 - x)

3 t + 5

\frac{d}{d x} (\frac{1 - cos ( x )}{1 + sin ( x )})

\frac{d}{d x} (- \frac{e ^{x - 1} ( x - 3 )}{( x - 1 ) ^{3}})

What is the limit as x approaches pi/2 of ln(sin(x)) ?
The limit as x approaches pi/2 of ln(sin(x)) is 0