What is (\partial)/(\partial x)(x^2-7xy+y) ?

The answer to (\partial)/(\partial x)(x^2-7xy+y) is 2x-7y

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(\partial)/(\partial x)(x^2-7xy+y)

\frac{\partial}{\partial x} (x^{2} - 7 x y + y)

2 x - 7 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 7 x y + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (7 x y) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (7 x y) = 7 y

\frac{\partial}{\partial x} (y) = 0

= 2 x - 7 y + 0

Simplify

= 2 x - 7 y

\int csc^{2} (\frac{x}{5}) d x

\frac{\partial}{\partial x} (sin (x^{2} - 7 x y))

\int_{0}^{\infty} e^{- x} x d x

\frac{\partial}{\partial z} (sin (x))

\frac{\partial}{\partial x} (e^{- 8 y} sin (8 x))

What is (\partial)/(\partial x)(x^2-7xy+y) ?
The answer to (\partial)/(\partial x)(x^2-7xy+y) is 2x-7y