What is the derivative of y=-2sin(x^2) ?

The derivative of y=-2sin(x^2) is -4xcos(x^2)

What is the first derivative of y=-2sin(x^2) ?

The first derivative of y=-2sin(x^2) is -4xcos(x^2)

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derivative of

y = - 2 sin (x^{2})

- 4 x cos (x^{2})

Solution steps

\frac{d}{d x} (- 2 sin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (x^{2}))

Apply the chain rule:

cos (x^{2}) \frac{d}{d x} (x^{2})

= cos (x^{2}) \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - 2 cos (x^{2}) \cdot 2 x

Simplify

= - 4 x cos (x^{2})

\int (2 x^{2} + 1) e^{x^{2}} d x

\int e^{6 t} cos (2 t) d t

\int_{0}^{2 π} 3 sin (2 t) d t

\frac{d}{d x} (ln (\frac{8 x}{x + 5}))

x \to 5 lim (\frac{1}{( x - 5 ) ^{3}})

What is the derivative of y=-2sin(x^2) ?
The derivative of y=-2sin(x^2) is -4xcos(x^2)
What is the first derivative of y=-2sin(x^2) ?
The first derivative of y=-2sin(x^2) is -4xcos(x^2)