What is the derivative of 2^xln^2(2) ?

The derivative of 2^xln^2(2) is ln^3(2)*2^x

What is the first derivative of 2^xln^2(2) ?

The first derivative of 2^xln^2(2) is ln^3(2)*2^x

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\frac{d}{d x} (2^{x} ln^{2} (2))

ln^{3} (2) \cdot 2^{x}

Solution steps

\frac{d}{d x} (2^{x} ln^{2} (2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln^{2} (2) \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= ln^{2} (2) \cdot 2^{x} ln (2)

Simplify

ln^{2} (2) \cdot 2^{x} ln (2) : ln^{3} (2) \cdot 2^{x}

= ln^{3} (2) \cdot 2^{x}

9 x + 11, 7 x + 14, [23, 13]

\frac{\partial}{\partial y} (e^{y} sin (x))

\frac{( 4 s - 18 )}{s ^{2} - 6 s + 10}

\frac{d y}{d t} = - 3 y + 4 cos (2 t)

What is the derivative of 2^xln^2(2) ?
The derivative of 2^xln^2(2) is ln^3(2)*2^x
What is the first derivative of 2^xln^2(2) ?
The first derivative of 2^xln^2(2) is ln^3(2)*2^x