What is the solution for (7xy^2-2y)+(7x^2y-2x)y^'=0 ?

The solution for (7xy^2-2y)+(7x^2y-2x)y^'=0 is y=(c_{1})/x

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(7xy^2-2y)+(7x^2y-2x)y^'=0

(7 x y^{2} - 2 y) + (7 x^{2} y - 2 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(7 x y^{2} - 2 y) + (7 x^{2} y - 2 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\int 20 x d x

\int \frac{x + 1}{( 2 - x ) ^{2}} d x

\int_{0}^{4} (e^{- 2 x} + 1) d x

\frac{d}{d x} (y^{x})

f (x) = 7 x + 6

What is the solution for (7xy^2-2y)+(7x^2y-2x)y^'=0 ?
The solution for (7xy^2-2y)+(7x^2y-2x)y^'=0 is y=(c_{1})/x