What is the tangent of x^4+2x^2+3,\at x=-2 ?

The tangent of x^4+2x^2+3,\at x=-2 is y=-40x-53

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tangent of x^4+2x^2+3,\at x=-2

tangent of

x^{4} + 2 x^{2} + 3, at x = - 2

y = - 40 x - 53

Solution steps

Find the tangent point:

(- 2, 27)

Find the slope of

y = x^{4} + 2 x^{2} + 3 : \frac{d y}{d x} = 4 x^{3} + 4 x

Compute the slope of

y = x^{4} + 2 x^{2} + 3

x = - 2 : m = - 40

Find the line with slope m=

- 40

and passing through

(- 2, 27) : y = - 40 x - 53

y = - 40 x - 53

f (x) = 4 e^{2 x^{3}}

\int_{- \infty}^{0} \frac{1}{7 - 4 x} d x

\int x^{2} e^{- 5 x} d x

\frac{\partial}{\partial x} (\frac{y + 1}{x})

\frac{d}{d x} (\frac{3}{( 1 - x ) ^{2}})

What is the tangent of x^4+2x^2+3,\at x=-2 ?
The tangent of x^4+2x^2+3,\at x=-2 is y=-40x-53