What is the tangent of y=2sqrt(x)+1,\at x= 1/4 ?

The tangent of y=2sqrt(x)+1,\at x= 1/4 is y=2x+3/2

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tangent of y=2sqrt(x)+1,\at x= 1/4

tangent of

y = 2 x + 1, at x = \frac{1}{4}

y = 2 x + \frac{3}{2}

Solution steps

Find the tangent point:

(\frac{1}{4}, 2)

Find the slope of

y = 2 x + 1 : \frac{d y}{d x} = \frac{1}{x}

Compute the slope of

y = 2 x + 1

x = \frac{1}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{1}{4}, 2) : y = 2 x + \frac{3}{2}

y = 2 x + \frac{3}{2}

\frac{s ^{2}}{( s - 3 ) ( s ^{2} + 5 )}

n = 0 \sum \infty \frac{e ^{n}}{n ^{2}}

\frac{\partial}{\partial z} (2 x z^{3} e^{y^{2}})

f (x) = t^{4} cos (t)

\int_{5}^{9} x^{2} d x

What is the tangent of y=2sqrt(x)+1,\at x= 1/4 ?
The tangent of y=2sqrt(x)+1,\at x= 1/4 is y=2x+3/2