What is (\partial)/(\partial y)(x^2+z^2) ?

The answer to (\partial)/(\partial y)(x^2+z^2) is 0

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(\partial)/(\partial y)(x^2+z^2)

\frac{\partial}{\partial y} (x^{2} + z^{2})

0

Solution steps

\frac{\partial}{\partial y} (x^{2} + z^{2})

Treat

x, z

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{\partial}{\partial x} (a)

f (x) = (\frac{( x - 3 )}{( x + 2 )})^{2} x = - 1

\int \frac{e ^{x}}{( e ^{x} + 1 ) ^{3}} d x

y^{^{'}} = ry (1 - \frac{y}{k})

\frac{d}{d x} ((x^{3} - 2)^{5})

What is (\partial)/(\partial y)(x^2+z^2) ?
The answer to (\partial)/(\partial y)(x^2+z^2) is 0