What is (\partial)/(\partial x)((2x+3)/(4y-1)) ?

The answer to (\partial)/(\partial x)((2x+3)/(4y-1)) is 2/(4y-1)

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(\partial)/(\partial x)((2x+3)/(4y-1))

\frac{\partial}{\partial x} (\frac{2 x + 3}{4 y - 1})

\frac{2}{4 y - 1}

Solution steps

\frac{\partial}{\partial x} (\frac{2 x + 3}{4 y - 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4 y - 1} \frac{\partial}{\partial x} (2 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4 y - 1} (\frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (3))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (3) = 0

= \frac{1}{4 y - 1} (2 + 0)

Simplify

\frac{1}{4 y - 1} (2 + 0) : \frac{2}{4 y - 1}

= \frac{2}{4 y - 1}

(90, 62536), (950, 9000)

\frac{d}{d t} (\frac{A e ^{m t}}{B + C e ^{m t}})

\frac{\partial}{\partial x} (y^{2} (x + y)^{- 2})

\int (tan (\frac{x}{14}))^{5} d x

11 x y^{^{'}} + y = 132 x

What is (\partial)/(\partial x)((2x+3)/(4y-1)) ?
The answer to (\partial)/(\partial x)((2x+3)/(4y-1)) is 2/(4y-1)