What is derivative of f(x)=(t^6+1)^{500} ?

The answer to derivative of f(x)=(t^6+1)^{500} is (dt)/(dx)=0

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derivative of f(x)=(t^6+1)^{500}

derivative of

f (x) = (t^{6} + 1)^{500}

\frac{d t}{d x} = 0

Solution steps

f (x) = (t^{6} + 1)^{500}

Treat

t

t (x)

Differentiate both sides:

0 = 3000 (t^{6} + 1)^{499} t^{5} \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

2 x \frac{d y}{d x} = 2 x e^{x} - 2 y + 6 x^{2}

\int \frac{1}{3 - 8 x} d x

- \frac{x}{( 25 - x ^{2} ) ^{\frac{1}{2}}}

(125 + x)^{- \frac{1}{3}}

y^{^{''}} + 2 y^{^{'}} + y = 14 e^{- t}

What is derivative of f(x)=(t^6+1)^{500} ?
The answer to derivative of f(x)=(t^6+1)^{500} is (dt)/(dx)=0