What is (\partial)/(\partial x)(-x+y) ?

The answer to (\partial)/(\partial x)(-x+y) is -1

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(\partial)/(\partial x)(-x+y)

\frac{\partial}{\partial x} (- x + y)

- 1

Solution steps

\frac{\partial}{\partial x} (- x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= - 1 + 0

Simplify

= - 1

\int x^{2} tan^{3} (x^{3}) d x

(x^{2} + 4) y^{^{'}} + 3 x y = x, y (0) = 1

9 x^{4} - 9 x^{2}, 8 x^{2}

\int_{0}^{\frac{1}{10}} \frac{1}{( 100 x ^{2} + 1 ) ^{\frac{3}{2}}} d x

\int \frac{( sin ( x ) )}{cos ^{2} ( x )} d x

What is (\partial)/(\partial x)(-x+y) ?
The answer to (\partial)/(\partial x)(-x+y) is -1