What is (\partial)/(\partial x)(10sin(xy)) ?

The answer to (\partial)/(\partial x)(10sin(xy)) is 10cos(xy)y

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(\partial)/(\partial x)(10sin(xy))

\frac{\partial}{\partial x} (10 sin (x y))

10 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (10 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 10 cos (x y) y

\int (12 x + 7) d x

x \to 4 lim (\frac{1}{x - 3})

- \frac{170 t}{( t + 4 ) ^{2}}

x \to 1 + lim (\frac{3}{1 - x})

\frac{d y}{d x} = 3 x + x y

What is (\partial)/(\partial x)(10sin(xy)) ?
The answer to (\partial)/(\partial x)(10sin(xy)) is 10cos(xy)y