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Popular >

derivative of sqrt(x^3)+4x^2-6x+1

Solution

\frac{d}{d x} (x^{3} + 4 x^{2} - 6 x + 1)

Solution

8 x + \frac{3 x}{2} - 6

Solution steps

\frac{d}{d x} (x^{3} + 4 x^{2} - 6 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = \frac{3 x}{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (1) = 0

= \frac{3 x}{2} + 8 x - 6 + 0

Simplify

= 8 x + \frac{3 x}{2} - 6

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20y^{''}-11y^'-3y=0

20 y^{^{''}} - 11 y^{^{'}} - 3 y = 0

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\int 5 sin^{3} (5 x co) s^{3} 5 x d x

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\int_{9}^{10} \frac{1}{( x - 9 ) ^{\frac{5}{4}}} d x

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\frac{d}{d x} (\frac{x}{2} - tan (x))

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\int sec (x) tan^{3} (x) d x

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(x^3)+4x^2-6x+1 ?
The derivative of sqrt(x^3)+4x^2-6x+1 is 8x+(3sqrt(x))/2-6
What is the first derivative of sqrt(x^3)+4x^2-6x+1 ?
The first derivative of sqrt(x^3)+4x^2-6x+1 is 8x+(3sqrt(x))/2-6