What is the derivative of 6x^3-4x^2+5x ?

The derivative of 6x^3-4x^2+5x is 18x^2-8x+5

What is the first derivative of 6x^3-4x^2+5x ?

The first derivative of 6x^3-4x^2+5x is 18x^2-8x+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (6 x^{3} - 4 x^{2} + 5 x)

18 x^{2} - 8 x + 5

Solution steps

\frac{d}{d x} (6 x^{3} - 4 x^{2} + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (5 x)

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (5 x) = 5

= 18 x^{2} - 8 x + 5

f (x) = \frac{9 x}{x + 4}, at x = 8

\int - \frac{1}{4} sin (2 x) d x

f (x) = \frac{6 x}{x + 6}

\frac{d}{d x} (ln (3 x^{2} + 5))

36 y^{^{''}} - 12 y^{^{'}} + y = 0

What is the derivative of 6x^3-4x^2+5x ?
The derivative of 6x^3-4x^2+5x is 18x^2-8x+5
What is the first derivative of 6x^3-4x^2+5x ?
The first derivative of 6x^3-4x^2+5x is 18x^2-8x+5