What is the integral of 28x^3-15x^2+8x ?

The integral of 28x^3-15x^2+8x is 7x^4-5x^3+4x^2+C

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integral of 28x^3-15x^2+8x

\int 28 x^{3} - 15 x^{2} + 8 x d x

7 x^{4} - 5 x^{3} + 4 x^{2} + C

Solution steps

\int 28 x^{3} - 15 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 28 x^{3} d x - \int 15 x^{2} d x + \int 8 x d x

\int 28 x^{3} d x = 7 x^{4}

\int 15 x^{2} d x = 5 x^{3}

\int 8 x d x = 4 x^{2}

= 7 x^{4} - 5 x^{3} + 4 x^{2}

Add a constant to the solution

= 7 x^{4} - 5 x^{3} + 4 x^{2} + C

\frac{x - 7}{- 5 x - 10}

\frac{d}{d x} (x^{n} ln (x))

\frac{9}{( s + 3 ) ^{2}}

x \to 4 lim (e^{4} - x)

\frac{d}{d x} (- \frac{4}{5} e^{(\frac{2}{3} x)})

What is the integral of 28x^3-15x^2+8x ?
The integral of 28x^3-15x^2+8x is 7x^4-5x^3+4x^2+C