What is the limit as n approaches infinity of 4n ?

The limit as n approaches infinity of 4n is infinity

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limit as n approaches infinity of 4n

n \to \infty lim (4 n)

\infty

Solution steps

n \to \infty lim (4 n)

Apply Infinity Property:

x \to \infty lim (a x^{n} + \dots + b x + c) = \infty, a > 0,

n is odd

a = 4, n = 1

= \infty

\frac{\partial}{\partial x} (2 x^{\frac{1}{2}} y^{\frac{1}{3}})

y^{^{'}} = \frac{y}{2}

\frac{d}{d x} (- \frac{1}{ln ( 10 ) x ^{2}})

(x - 2) e^{(- 2 y)} = \frac{d y}{d x}

f (x) = sin (arcsin (6 x))

What is the limit as n approaches infinity of 4n ?
The limit as n approaches infinity of 4n is infinity