What is the solution for (dy)/(dx)=(x+y+2)/(x+y-4) ?

The solution for (dy)/(dx)=(x+y+2)/(x+y-4) is y=-x-3\W(-1/(6e^{(2x+c_{1))/3}})+1

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(dy)/(dx)=(x+y+2)/(x+y-4)

\frac{d y}{d x} = \frac{x + y + 2}{x + y - 4}

y = - x - 3 W (- \frac{1}{6 e ^{\frac{2 x + c _{1}}{3}}}) + 1

Solution steps

\frac{d y}{d x} = \frac{x + y + 2}{x + y - 4}

Solve using substitution:

y = - x - 3 W (- \frac{1}{6 e ^{\frac{2 x + c _{1}}{3}}}) + 1

y = - x - 3 W (- \frac{1}{6 e ^{\frac{2 x + c _{1}}{3}}}) + 1

x \to 0 lim (x^{2} + 2)

\frac{d}{d x} (cos (2 x) 2)

\int_{- 3}^{- 2} 2 x (4 - x^{2})^{3} d x

\frac{d ^{2}}{d x ^{2}} (\frac{1}{1 + x ^{2}})

\int \frac{1}{( 3 - x ) 2 - x} d x

What is the solution for (dy)/(dx)=(x+y+2)/(x+y-4) ?
The solution for (dy)/(dx)=(x+y+2)/(x+y-4) is y=-x-3\W(-1/(6e^{(2x+c_{1))/3}})+1