What is the derivative of f(x)=(3x^3+1)^2 ?

The derivative of f(x)=(3x^3+1)^2 is 18x^2(3x^3+1)

What is the first derivative of f(x)=(3x^3+1)^2 ?

The first derivative of f(x)=(3x^3+1)^2 is 18x^2(3x^3+1)

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derivative of

f (x) = (3 x^{3} + 1)^{2}

18 x^{2} (3 x^{3} + 1)

Solution steps

\frac{d}{d x} ((3 x^{3} + 1)^{2})

Apply the chain rule:

2 (3 x^{3} + 1) \frac{d}{d x} (3 x^{3} + 1)

= 2 (3 x^{3} + 1) \frac{d}{d x} (3 x^{3} + 1)

\frac{d}{d x} (3 x^{3} + 1) = 9 x^{2}

= 2 (3 x^{3} + 1) \cdot 9 x^{2}

Simplify

= 18 x^{2} (3 x^{3} + 1)

f (x) = sin (x)

x \to - 8 - lim (x^{2} + \frac{2}{x + 8})

\int tan^{2} (x se) c^{2} x d x

\int 4 x^{3} - 3 x + 5 d x

\frac{d}{d x} (sin^{4} (x) + cos^{4} (x))

What is the derivative of f(x)=(3x^3+1)^2 ?
The derivative of f(x)=(3x^3+1)^2 is 18x^2(3x^3+1)
What is the first derivative of f(x)=(3x^3+1)^2 ?
The first derivative of f(x)=(3x^3+1)^2 is 18x^2(3x^3+1)