What is the solution for (dy)/(dx)=(y+4)/(2-y) ?

The solution for (dy)/(dx)=(y+4)/(2-y) is y=-6\W(-1/(6e^{(-x-c_{1))/6}})-4

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(dy)/(dx)=(y+4)/(2-y)

\frac{d y}{d x} = \frac{y + 4}{2 - y}

y = - 6 W (- \frac{1}{6 e ^{\frac{- x - c _{1}}{6}}}) - 4

Solution steps

\frac{d y}{d x} = \frac{y + 4}{2 - y}

Solve separable ODE:

y = - 6 W (- \frac{1}{6 e ^{\frac{- x - c _{1}}{6}}}) - 4

y = - 6 W (- \frac{1}{6 e ^{\frac{- x - c _{1}}{6}}}) - 4

\frac{d q}{d t} = k (q - 70)

\frac{d}{d x} (6^{- x})

x^{3}

x \to 0 + lim (\frac{csc ( 2 x )}{x})

y^{^{''}} - y = 0, y (0) = 2

What is the solution for (dy)/(dx)=(y+4)/(2-y) ?
The solution for (dy)/(dx)=(y+4)/(2-y) is y=-6\W(-1/(6e^{(-x-c_{1))/6}})-4