What is the integral of (\sqrt[5]{x}+\sqrt[6]{x}) ?

The integral of (\sqrt[5]{x}+\sqrt[6]{x}) is 5/6 x^{6/5}+6/7 x^{7/6}+C

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integral of (\sqrt[5]{x}+\sqrt[6]{x})

\frac{5}{6} x^{\frac{6}{5}} + \frac{6}{7} x^{\frac{7}{6}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{5}{6} x^{\frac{6}{5}} + \frac{6}{7} x^{\frac{7}{6}}

Add a constant to the solution

= \frac{5}{6} x^{\frac{6}{5}} + \frac{6}{7} x^{\frac{7}{6}} + C

x \to 0 lim (\frac{1}{x ^{2} ( x - 7 )})

\frac{d}{d x} (ln (y) + y^{2} + cos (x))

y^{^{''}} + 2 y^{^{'}} + y = sin (2 t)

\int_{- \infty}^{6} x e^{\frac{x}{2}} d x

y^{^{'}} = \frac{1}{1 + y}

What is the integral of (\sqrt[5]{x}+\sqrt[6]{x}) ?
The integral of (\sqrt[5]{x}+\sqrt[6]{x}) is 5/6 x^{6/5}+6/7 x^{7/6}+C