What is the derivative of 2x^{1/3} ?

The derivative of 2x^{1/3} is 2/(3x^{2/3)}

What is the first derivative of 2x^{1/3} ?

The first derivative of 2x^{1/3} is 2/(3x^{2/3)}

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derivative of

2 x^{\frac{1}{3}}

\frac{2}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (2 x^{\frac{1}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

2 \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{2}{3 x ^{\frac{2}{3}}}

= \frac{2}{3 x ^{\frac{2}{3}}}

\int (2 x + 1) sin (x) d x

\int \frac{x}{x ^{3} + x ^{2} + x + 1} d x

\frac{d}{d x} (a^{2} x + a^{2} y + b^{2} x + b^{2} y)

\frac{d}{d x} (\frac{2}{3} (5 - 2 x^{2})^{3})

y = - 3 cot (2 x) sec (2 x)

What is the derivative of 2x^{1/3} ?
The derivative of 2x^{1/3} is 2/(3x^{2/3)}
What is the first derivative of 2x^{1/3} ?
The first derivative of 2x^{1/3} is 2/(3x^{2/3)}