What is the tangent of y=3tan(x),\at x= pi/6 ?

The tangent of y=3tan(x),\at x= pi/6 is y=4x+sqrt(3)-(2pi)/3

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tangent of y=3tan(x),\at x= pi/6

tangent of

y = 3 tan (x), at x = \frac{π}{6}

y = 4 x + 3 - \frac{2 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 3)

Find the slope of

y = 3 tan (x) : \frac{d y}{d x} = 3 sec^{2} (x)

Compute the slope of

y = 3 tan (x)

x = \frac{π}{6} : m = 4

Find the line with slope m=

4

and passing through

(\frac{π}{6}, 3) : y = 4 x + 3 - \frac{2 π}{3}

y = 4 x + 3 - \frac{2 π}{3}

\int 8^{3} x d x

y^{^{'}} - \frac{6}{x} y = \frac{y ^{5}}{x ^{7}}

\int \frac{1}{x ^{2} - 2 x + 17} d x

x \to 0 lim (ln (x^{2}))

ln (3 x^{2} + 7 y^{2})

What is the tangent of y=3tan(x),\at x= pi/6 ?
The tangent of y=3tan(x),\at x= pi/6 is y=4x+sqrt(3)-(2pi)/3