What is the derivative of (\sqrt[3]{x}/(x-3)) ?

The derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

What is the first derivative of (\sqrt[3]{x}/(x-3)) ?

The first derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

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Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 3) = 1

Simplify

\int \frac{1}{e ^{5 y}} d y

\frac{4 s + 1}{s ^{3} - 3 s ^{2} + 3 s - 1}

\frac{( 10 s - 3 )}{s ^{2} - 4 s - 29}

\frac{d}{d x} (\frac{ln ( x )}{x})

What is the derivative of (\sqrt[3]{x}/(x-3)) ?
The derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}
What is the first derivative of (\sqrt[3]{x}/(x-3)) ?
The first derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}