What is the integral of sec^7(4x)tan(4x) ?

The integral of sec^7(4x)tan(4x) is 1/28 sec^7(4x)+C

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integral of sec^7(4x)tan(4x)

\int sec^{7} (4 x) tan (4 x) d x

\frac{1}{28} sec^{7} (4 x) + C

Solution steps

\int sec^{7} (4 x) tan (4 x) d x

Apply u-substitution

: \int sec^{7} (u) tan (u) \frac{1}{4} d u

= \int sec^{7} (u) tan (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sec^{7} (u) tan (u) d u

Apply u-substitution

: \int v^{6} d v

= \frac{1}{4} \cdot \int v^{6} d v

Apply the Power Rule

: \frac{v ^{7}}{7}

= \frac{1}{4} \cdot \frac{v ^{7}}{7}

Substitute back

= \frac{1}{4} \cdot \frac{sec ^{7} ( 4 x )}{7}

Simplify

\frac{1}{4} \cdot \frac{sec ^{7} ( 4 x )}{7} : \frac{1}{28} sec^{7} (4 x)

= \frac{1}{28} sec^{7} (4 x)

Add a constant to the solution

= \frac{1}{28} sec^{7} (4 x) + C

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What is the integral of sec^7(4x)tan(4x) ?
The integral of sec^7(4x)tan(4x) is 1/28 sec^7(4x)+C