What is the limit as x approaches 0+of ln(4sin(x)) ?

The limit as x approaches 0+of ln(4sin(x)) is -infinity

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limit as x approaches 0+of ln(4sin(x))

x \to 0 + lim (ln (4 sin (x)))

- \infty

Solution steps

x \to 0 + lim (ln (4 sin (x)))

Apply the Limit Chain Rule:

- \infty

= - \infty

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What is the limit as x approaches 0+of ln(4sin(x)) ?
The limit as x approaches 0+of ln(4sin(x)) is -infinity