What is the derivative of 3e^{3x} ?

The derivative of 3e^{3x} is 9e^{3x}

What is the first derivative of 3e^{3x} ?

The first derivative of 3e^{3x} is 9e^{3x}

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derivative of

3 e^{3 x}

9 e^{3 x}

Solution steps

\frac{d}{d x} (3 e^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{3 x})

Apply the chain rule:

e^{3 x} \frac{d}{d x} (3 x)

= e^{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 3 e^{3 x} \cdot 3

Simplify

= 9 e^{3 x}

4 y^{^{'''}} + 12 y^{^{''}} - 16 y^{^{'}} - 48 y = 0

f (x) = 8 x^{3} - 24 x^{2} - 193 x + 48

\frac{d}{d x} (sin (x) (x^{2} - 27 x + 6))

\frac{d}{d x} (ln (1 + x))

n = 1 \sum \infty (sin (9))^{n}

What is the derivative of 3e^{3x} ?
The derivative of 3e^{3x} is 9e^{3x}
What is the first derivative of 3e^{3x} ?
The first derivative of 3e^{3x} is 9e^{3x}