What is the integral from 1 to 2 of 1/(x^3) ?

The integral from 1 to 2 of 1/(x^3) is 3/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of 1/(x^3)

\int_{1}^{2} \frac{1}{x ^{3}} d x

\frac{3}{8}

Decimal Notation

0.375

Solution steps

\int_{1}^{2} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{2}

= [- \frac{1}{2 x ^{2}}]_{1}^{2}

Compute the boundaries:

\frac{3}{8}

= \frac{3}{8}

f (x) = x^{2} + x, (2, 6)

\frac{d}{d x} (cos^{3} (x) + sin^{3} (x))

x \to \infty lim (\frac{3}{2})

\int_{0}^{π} 2 π x (sin (x)) d x

\int cos (2 + t) d t

What is the integral from 1 to 2 of 1/(x^3) ?
The integral from 1 to 2 of 1/(x^3) is 3/8