What is the d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) ?

The d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) is (x(36-9x^2-8y^2))/(6sqrt(36-9x^2-4y^2))

What is the first d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) ?

The first d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) is (x(36-9x^2-8y^2))/(6sqrt(36-9x^2-4y^2))

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\frac{d}{d y} (x y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

\frac{x ( 36 - 9 x ^{2} - 8 y ^{2} )}{6 36 - 9 x ^{2} - 4 y ^{2}}

Solution steps

\frac{d}{d y} (x y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9}

= x (\frac{d y}{d y} 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9} + \frac{d}{d y} (1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9}) y)

\frac{d y}{d y} = 1

\frac{d}{d y} (1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9}) = - \frac{2 y}{3 - 4 y ^{2} + 36 - 9 x ^{2}}

= x (1 \cdot 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9} + (- \frac{2 y}{3 - 4 y ^{2} + 36 - 9 x ^{2}}) y)

Simplify

x (1 \cdot 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9} + (- \frac{2 y}{3 - 4 y ^{2} + 36 - 9 x ^{2}}) y) : \frac{x ( 36 - 9 x ^{2} - 8 y ^{2} )}{6 36 - 9 x ^{2} - 4 y ^{2}}

= \frac{x ( 36 - 9 x ^{2} - 8 y ^{2} )}{6 36 - 9 x ^{2} - 4 y ^{2}}

\int \frac{5 x ^{2} + 3 x - 1}{x ^{3} - 2 x ^{2} + x - 2} d x

x \to 0 lim (\frac{x ^{2} - 3 x}{2 x})

\int_{- \infty}^{0} 15 x e^{3 x} d x

f (x) = 3 x + 4

\frac{1 + x f ( x )}{x}

What is the d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) ?
The d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) is (x(36-9x^2-8y^2))/(6sqrt(36-9x^2-4y^2))
What is the first d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) ?
The first d/(dy)(xysqrt(1-(x^2)/4-(y^2)/9)) is (x(36-9x^2-8y^2))/(6sqrt(36-9x^2-4y^2))