What is the slope of (-pi,0),(-pi/2 ,4) ?

The slope of (-pi,0),(-pi/2 ,4) is m= 8/pi

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slope of (-pi,0),(-pi/2 ,4)

slope

(- π, 0), (- \frac{π}{2}, 4)

m = \frac{8}{π}

Solution steps

Slope between two points: Slope

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (- π, 0), (x_{2}, y_{2}) = (- \frac{π}{2}, 4)

m = \frac{4 - 0}{- \frac{π}{2} - ( - π )}

Refine

m = \frac{8}{π}

\frac{2}{y}

\int \frac{x ^{2} - 2}{2 x} d x

\frac{\partial}{\partial x} (\frac{7 x - 5 y}{y ^{2} + 2 x ^{2}})

\frac{d}{d y} (3 x^{2} y)

\frac{d y}{d x} + 3 y = 0

What is the slope of (-pi,0),(-pi/2 ,4) ?
The slope of (-pi,0),(-pi/2 ,4) is m= 8/pi