What is the derivative of y=3x^2+12x+6 ?

The derivative of y=3x^2+12x+6 is 6x+12

What is the first derivative of y=3x^2+12x+6 ?

The first derivative of y=3x^2+12x+6 is 6x+12

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derivative of

y = 3 x^{2} + 12 x + 6

6 x + 12

Solution steps

\frac{d}{d x} (3 x^{2} + 12 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (12 x) + \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (6) = 0

= 6 x + 12 + 0

Simplify

= 6 x + 12

y^{^{''}} + 4 y^{^{'}} + 4 y = 8 x^{2}

\frac{d}{d x} (x e^{x} y)

\frac{d ^{3}}{d x ^{3}} (cos (x) - sin (x))

\int \frac{6}{x ( x + 2 )} d x

x \to 3 + lim (\frac{∣ x - 2 ∣}{x - 2})

What is the derivative of y=3x^2+12x+6 ?
The derivative of y=3x^2+12x+6 is 6x+12
What is the first derivative of y=3x^2+12x+6 ?
The first derivative of y=3x^2+12x+6 is 6x+12