What is (\partial)/(\partial t)(cos^2(t)) ?

The answer to (\partial)/(\partial t)(cos^2(t)) is -sin(2t)

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(\partial)/(\partial t)(cos^2(t))

\frac{\partial}{\partial t} (cos^{2} (t))

- sin (2 t)

Solution steps

\frac{\partial}{\partial t} (cos^{2} (t))

Apply the chain rule:

2 cos (t) \frac{\partial}{\partial t} (cos (t))

= 2 cos (t) \frac{\partial}{\partial t} (cos (t))

\frac{\partial}{\partial t} (cos (t)) = - sin (t)

= 2 cos (t) (- sin (t))

Simplify

2 cos (t) (- sin (t)) : - sin (2 t)

= - sin (2 t)

x \to 0 - lim (2 x + c)

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2}}

y^{^{'''}} + 4 y^{^{''}} - 5 y^{^{'}} = 0

\int_{0}^{8} (8 x - x^{2}) d x

\int (8 x - 12) (4 x^{2} - 12 x)^{4} d x

What is (\partial)/(\partial t)(cos^2(t)) ?
The answer to (\partial)/(\partial t)(cos^2(t)) is -sin(2t)