What is the integral from 0 to 1 of (17)/(x^5) ?

The integral from 0 to 1 of (17)/(x^5) is diverges

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integral from 0 to 1 of (17)/(x^5)

\int_{0}^{1} \frac{17}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{17}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 17 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 17 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int x x^{2} + 2 x + 2 d x

\int x sin (- 2 x) d x

9 y^{^{''}} + 24 y^{^{'}} + 16 y = 0

(\frac{1}{1 + x ^{2}})^{^{'}}

\int_{- 1}^{5} 3 x^{2} + 6 x d x

What is the integral from 0 to 1 of (17)/(x^5) ?
The integral from 0 to 1 of (17)/(x^5) is diverges