What is the integral from 0 to 1 of (1/(x^2)) ?

The integral from 0 to 1 of (1/(x^2)) is diverges

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integral from 0 to 1 of (1/(x^2))

\int_{0}^{1} (\frac{1}{x ^{2}}) d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{1}

= [- \frac{1}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int cot^{3} (\frac{x}{2}) csc^{2} (\frac{x}{2}) d x

\frac{d}{d x} (\frac{( x ^{2} - 2 x ) ^{3}}{5 x})

\int 8 x^{3} e^{4 x} d x

e^{- 2 t} t^{\frac{3}{2}}

f (x) = - 8 x^{2} - 7 x, at x = - 4

What is the integral from 0 to 1 of (1/(x^2)) ?
The integral from 0 to 1 of (1/(x^2)) is diverges