What is the integral of (x^2-3x+12)/((x^2-4x+11)^2) ?

The integral of (x^2-3x+12)/((x^2-4x+11)^2) is

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integral of (x^2-3x+12)/((x^2-4x+11)^2)

\int \frac{x ^{2} - 3 x + 12}{( x ^{2} - 4 x + 11 ) ^{2}} d x

\frac{1}{14 7} x arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} x sin (2 arctan (\frac{1}{7} (x - 2))) + \frac{15}{14 7} arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} sin (2 arctan (\frac{1}{7} (x - 2))) - \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{14 7 ( x ^{2} - 4 x + 11 )} - \frac{1}{2 ( x ^{2} - 4 x + 11 )} + C

Solution steps

\int \frac{x ^{2} - 3 x + 12}{( x ^{2} - 4 x + 11 ) ^{2}} d x

Take the partial fraction of

\frac{x ^{2} - 3 x + 12}{( x ^{2} - 4 x + 11 ) ^{2}} : \frac{1}{x ^{2} - 4 x + 11} + \frac{x + 1}{( x ^{2} - 4 x + 11 ) ^{2}}

= \int \frac{1}{x ^{2} - 4 x + 11} + \frac{x + 1}{( x ^{2} - 4 x + 11 ) ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{2} - 4 x + 11} d x + \int \frac{x + 1}{( x ^{2} - 4 x + 11 ) ^{2}} d x

\int \frac{1}{x ^{2} - 4 x + 11} d x = \frac{1}{7} arctan (\frac{x - 2}{7})

\int \frac{x + 1}{( x ^{2} - 4 x + 11 ) ^{2}} d x = \frac{1}{28 7} (2 arctan (\frac{x - 2}{7}) + sin (2 arctan (\frac{x - 2}{7}))) (x + 1) - \frac{1}{14} \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{7 ( x ^{2} - 4 x + 11 )} + \frac{7}{x ^{2} - 4 x + 11}

= \frac{1}{7} arctan (\frac{x - 2}{7}) + \frac{1}{28 7} (2 arctan (\frac{x - 2}{7}) + sin (2 arctan (\frac{x - 2}{7}))) (x + 1) - \frac{1}{14} \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{7 ( x ^{2} - 4 x + 11 )} + \frac{7}{x ^{2} - 4 x + 11}

Simplify

\frac{1}{7} arctan (\frac{x - 2}{7}) + \frac{1}{28 7} (2 arctan (\frac{x - 2}{7}) + sin (2 arctan (\frac{x - 2}{7}))) (x + 1) - \frac{1}{14} \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{7 ( x ^{2} - 4 x + 11 )} + \frac{7}{x ^{2} - 4 x + 11} : \frac{1}{14 7} x arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} x sin (2 arctan (\frac{1}{7} (x - 2))) + \frac{15}{14 7} arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} sin (2 arctan (\frac{1}{7} (x - 2))) - \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{14 7 ( x ^{2} - 4 x + 11 )} - \frac{1}{2 ( x ^{2} - 4 x + 11 )}

= \frac{1}{14 7} x arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} x sin (2 arctan (\frac{1}{7} (x - 2))) + \frac{15}{14 7} arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} sin (2 arctan (\frac{1}{7} (x - 2))) - \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{14 7 ( x ^{2} - 4 x + 11 )} - \frac{1}{2 ( x ^{2} - 4 x + 11 )}

Add a constant to the solution

= \frac{1}{14 7} x arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} x sin (2 arctan (\frac{1}{7} (x - 2))) + \frac{15}{14 7} arctan (\frac{1}{7} (x - 2)) + \frac{1}{28 7} sin (2 arctan (\frac{1}{7} (x - 2))) - \frac{( x - 2 ) ( arctan ( \frac{1}{7} ( x - 2 ) ) ( x ^{2} - 4 x + 11 ) + 7 ( x - 2 ) )}{14 7 ( x ^{2} - 4 x + 11 )} - \frac{1}{2 ( x ^{2} - 4 x + 11 )} + C

\frac{d}{d x} (\frac{1}{x ^{3}} - \frac{2}{x ^{2}})

(x^{4} + 7 x^{2} - 3)^{4}

f (x) = \frac{5}{x ^{2}}, at x = 1

\int \frac{x - 1}{x ^{2} + 3 x + 2} d x

\frac{d y}{d x} = (3 y)^{\frac{1}{2}} e^{x + 10}

What is the integral of (x^2-3x+12)/((x^2-4x+11)^2) ?
The integral of (x^2-3x+12)/((x^2-4x+11)^2) is