What is the integral from 0 to pi/4 of 1/(cos(x)) ?

The integral from 0 to pi/4 of 1/(cos(x)) is ln(1+sqrt(2))

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integral from 0 to pi/4 of 1/(cos(x))

\int_{0}^{\frac{π}{4}} \frac{1}{cos ( x )} d x

ln (1 + 2)

Decimal Notation

0.88137 \dots

Solution steps

\int_{0}^{\frac{π}{4}} \frac{1}{cos ( x )} d x

Rewrite using trig identities

= \int_{0}^{\frac{π}{4}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{0}^{\frac{π}{4}}

Compute the boundaries:

ln (1 + 2)

= ln (1 + 2)

\frac{\partial}{\partial x} (cos (x^{3}))

\frac{d}{d x} (cos (x^{2}) \cdot 2 x)

\frac{\partial}{\partial x} (x e^{y} - 1)

x^{2} + y^{2} = 27

\int_{1}^{x} \frac{e ^{- 3 t}}{t} d t

What is the integral from 0 to pi/4 of 1/(cos(x)) ?
The integral from 0 to pi/4 of 1/(cos(x)) is ln(1+sqrt(2))