What is the integral of (2-3sin(2x))/(cos(2x)) ?

The integral of (2-3sin(2x))/(cos(2x)) is ln|tan(2x)+sec(2x)|+3/2 ln|cos(2x)|+C

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integral of (2-3sin(2x))/(cos(2x))

\int \frac{2 - 3 sin ( 2 x )}{cos ( 2 x )} d x

ln ∣ tan (2 x) + sec (2 x) ∣ + \frac{3}{2} ln ∣ cos (2 x) ∣ + C

Solution steps

\int \frac{2 - 3 sin ( 2 x )}{cos ( 2 x )} d x

Expand

\frac{2 - 3 sin ( 2 x )}{cos ( 2 x )} : \frac{2}{cos ( 2 x )} - \frac{3 sin ( 2 x )}{cos ( 2 x )}

= \int \frac{2}{cos ( 2 x )} - \frac{3 sin ( 2 x )}{cos ( 2 x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{cos ( 2 x )} d x - \int \frac{3 sin ( 2 x )}{cos ( 2 x )} d x

\int \frac{2}{cos ( 2 x )} d x = ln ∣ tan (2 x) + sec (2 x) ∣

\int \frac{3 sin ( 2 x )}{cos ( 2 x )} d x = - \frac{3}{2} ln ∣ cos (2 x) ∣

= ln ∣ tan (2 x) + sec (2 x) ∣ - (- \frac{3}{2} ln ∣ cos (2 x) ∣)

Simplify

= ln ∣ tan (2 x) + sec (2 x) ∣ + \frac{3}{2} ln ∣ cos (2 x) ∣

Add a constant to the solution

= ln ∣ tan (2 x) + sec (2 x) ∣ + \frac{3}{2} ln ∣ cos (2 x) ∣ + C

\int \frac{4}{x - 5} d x

\int \frac{x ^{4}}{x ^{3} + 1} d x

x \to - 5 lim (- x + 2)

\int - 2 t cos (- t^{2}) d t

\frac{\partial}{\partial x} (\frac{( 2 x - y )}{2 x + y})

What is the integral of (2-3sin(2x))/(cos(2x)) ?
The integral of (2-3sin(2x))/(cos(2x)) is ln|tan(2x)+sec(2x)|+3/2 ln|cos(2x)|+C