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Popular >

integral from 0 to 3 of-x^2+9

Solution

\int_{0}^{3} - x^{2} + 9 d x

Solution

18

Solution steps

\int_{0}^{3} - x^{2} + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 9 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 9 d x = 27

= - 9 + 27

Simplify

= 18

Graph

Popular Examples

y^'=((y^2-1))/(2x),y(1)=-2

y^{^{'}} = \frac{( y ^{2} - 1 )}{2 x}, y (1) = - 2

(dy}{dt}=-\frac{3y)/t-2-t^{-4},y(1)=4

\frac{d y}{d t} = - \frac{3 y}{t} - 2 - t^{- 4}, y (1) = 4

limit as x approaches 2 of sqrt(x)

x \to 2 lim (x)

area x,x^3,4x,0 area

x, x^{3}, 4 x, 0

inverse oflaplace 1/(6s+1)inverse laplace

\frac{1}{6 s + 1}

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of-x^2+9 ?
The integral from 0 to 3 of-x^2+9 is 18