What is the derivative of x^2+2x+4 ?

The derivative of x^2+2x+4 is 2x+2

What is the first derivative of x^2+2x+4 ?

The first derivative of x^2+2x+4 is 2x+2

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derivative of

x^{2} + 2 x + 4

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

\frac{1}{s ( s + 2 ) ( s + 6 )}

\int_{- 1}^{1} \frac{1}{x ^{2} - 1} d x

n = 0 \sum \infty 1800 (\frac{1}{3})^{n}

f (x) = 4 x e^{x}, (0, 0)

\int x (4 + x)^{10} d x

What is the derivative of x^2+2x+4 ?
The derivative of x^2+2x+4 is 2x+2
What is the first derivative of x^2+2x+4 ?
The first derivative of x^2+2x+4 is 2x+2