What is the limit as x approaches 0 of sin(1/x) ?

The limit as x approaches 0 of sin(1/x) is diverges

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limit as x approaches 0 of sin(1/x)

x \to 0 lim (sin (\frac{1}{x}))

diverges

Solution steps

x \to 0 lim (sin (\frac{1}{x}))

Apply Limit Divergence Criterion:

diverges

= diverges

\int x csc (x^{2}) cot (x^{2}) d x

\int \frac{1}{( x ^{2} + 25 )} d x

y = \frac{5}{7} x + \frac{4}{3}

y^{^{''}} + 2 y = 3, y (0) = - 1, y^{^{'}} (0) = 2

\frac{d}{d x} (lo g_{5} (2 x^{3} + x^{2}))

What is the limit as x approaches 0 of sin(1/x) ?
The limit as x approaches 0 of sin(1/x) is diverges