What is the integral of sin(θ/2) ?

The integral of sin(θ/2) is -2cos(θ/2)+C

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integral of sin(θ/2)

\int sin (\frac{θ}{2}) d θ

- 2 cos (\frac{θ}{2}) + C

Solution steps

\int sin (\frac{θ}{2}) d θ

Apply u-substitution

: \int sin (u) \cdot 2 d u

= \int sin (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 2 (- cos (u))

Substitute back

u = \frac{θ}{2}

= 2 (- cos (\frac{θ}{2}))

Simplify

= - 2 cos (\frac{θ}{2})

Add a constant to the solution

= - 2 cos (\frac{θ}{2}) + C

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