What is the derivative of y=be^{e^3+x^3} ?

The derivative of y=be^{e^3+x^3} is be^{e^3+x^3}*3x^2

What is the first derivative of y=be^{e^3+x^3} ?

The first derivative of y=be^{e^3+x^3} is be^{e^3+x^3}*3x^2

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derivative of

y = b e^{e^{3} + x^{3}}

b e^{e^{3} + x^{3}} \cdot 3 x^{2}

Solution steps

\frac{d}{d x} (b e^{e^{3} + x^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (e^{e^{3} + x^{3}})

Apply the chain rule:

e^{e^{3} + x^{3}} \frac{d}{d x} (e^{3} + x^{3})

= e^{e^{3} + x^{3}} \frac{d}{d x} (e^{3} + x^{3})

\frac{d}{d x} (e^{3} + x^{3}) = 3 x^{2}

= b e^{e^{3} + x^{3}} \cdot 3 x^{2}

\frac{d}{d x} (2 lo g_{10} (x) - 3 x)

\int \frac{2 x ^{2}}{4 x - x ^{2}} d x

\frac{3 x + 4}{3 x - 4}

\int sec^{5} (x) - sec^{3} (x) d x

x (y + 1) d x + y (x - 1) d y = 0

What is the derivative of y=be^{e^3+x^3} ?
The derivative of y=be^{e^3+x^3} is be^{e^3+x^3}*3x^2
What is the first derivative of y=be^{e^3+x^3} ?
The first derivative of y=be^{e^3+x^3} is be^{e^3+x^3}*3x^2