What is the tangent of sqrt(1-x) ?

The tangent of sqrt(1-x) is y=-1/(2sqrt(1-a_{0))}x+sqrt(1-a_{0)}+(a_{0})/(2sqrt(1-a_{0))}

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tangent of sqrt(1-x)

tangent of

1 - x

y = - \frac{1}{2 1 - a _{0}} x + 1 - a_{0} + \frac{a _{0}}{2 1 - a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 1 - a_{0})

Find the slope of

y = 1 - x : \frac{d y}{d x} = - \frac{1}{2 1 - x}

Compute the slope of

y = 1 - x

x = a_{0} : m = - \frac{1}{2 1 - a _{0}}

Find the line with slope m=

- \frac{1}{2 1 - a _{0}}

and passing through

(a_{0}, 1 - a_{0}) : y = - \frac{1}{2 1 - a _{0}} x + 1 - a_{0} + \frac{a _{0}}{2 1 - a _{0}}

y = - \frac{1}{2 1 - a _{0}} x + 1 - a_{0} + \frac{a _{0}}{2 1 - a _{0}}

\frac{d}{d x} (\frac{9 x}{64 + x ^{2} + y ^{2}})

\frac{d}{d x} (- ln ∣ cos (x) ∣)

f (x) = (- 3 x^{2} - 3)^{4}

t \to 0 lim (cos (3 t))

\frac{\partial}{\partial z} (\frac{( x + y )}{( y + z )})

What is the tangent of sqrt(1-x) ?
The tangent of sqrt(1-x) is y=-1/(2sqrt(1-a_{0))}x+sqrt(1-a_{0)}+(a_{0})/(2sqrt(1-a_{0))}